-10x^2+100x-160=0

Solution for -10x^2+100x-160=0 equation:

-10x^2+100x-160=0

a = -10; b = 100; c = -160;
Δ = b2-4ac
Δ = 1002-4·(-10)·(-160)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-60}{2*-10}=\frac{-160}{-20}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+60}{2*-10}=\frac{-40}{-20}
=+2
$